In a ABC,PQ||BC and APAB=38, AC = 7.2 then AQ is (iamge)
In ΔAPQandΔABC,∠Aiscommon,∠APQ=∠ABCand∠AQP=∠ACB
[correspondinganglepairs] Hence the triangles are similar by AAA. So, APAB=AQAC⟹38=AQ7.2⟹AQ=2.7.