wiz-icon
MyQuestionIcon
MyQuestionIcon
23
You visited us 23 times! Enjoying our articles? Unlock Full Access!
Question

In a , AD is the bisector of ΔABC, meeting side BC at D. If AB = 10 cm, AC = 6 cm, BC = 12 cm, find BD.
323908.PNG

A
3.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 7.5

In ΔBADandΔDAC,BAD=DACABD=ACD

[sinceADiscommon,anglesoppositeequalsidesareequal].

Hence the triangles are similar by AA.

So, ACAB=DCDB610=12xx6x=12010x16x=120orx=7.5.

Hence BD = 7.5cm.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Square
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon