In a double-slit experiment, instead of taking slits of equal width, one slit is made twice as wide as the other. Then in the interference pattern
A
the intensities of both the maxima and the minima increase
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B
the intensity of the maxima increases and the minima has zero intensity
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C
the intensity of the maxima decreases and that of the minima increases
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D
the intensity of the maxima decreases and the minima has zero intensity
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Solution
The correct option is A the intensities of both the maxima and the minima increase Case 1: When slit are of equal width, if Io is intensity of light then,
Imax=Io+Io+2√IoIo=4Io
Imin=Io+Io−2√IoIo=0
Case 2: When slit are of unequal width, intensity from one slit would increase to twice then,
Inewmax=2Io+Io+2√2IoIo=5.83Io
Inewmin=2Io+Io−2√2IoIo=0.17Io
Therefore, intensities of both the maxima and the minima increase