In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1m away. A monochromatic light of wave length 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?
In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1m away. A monochromatic light of wave length 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?
The correct option is B 0.2 mm
In a double slit experiment, the two slits are 1 mm apart.
d = 1 mm = 10−3 m.
The screen is placed at a distance D = 1 m away. Monochromatic light of wave length
λ = 500 nm = 5 × 10−7 m is used.
The distance between two successive maxima or two successive minima is
λDd=5×10−710−3=5×10−4m=0.5mm
Ten maxima are contained within a distance
10 × 0.5 mm = 5 mm
For a single slit pattern we have
sinθ=λa
The width of the central maxima is
2D sin θ=2Dλa=5mm∴a=2Dλ5×10−3=2×5×10−75×10−3=2×10−4m=0.2mm
0.2 mm
In a double slit experiment, the two slits are 1 mm apart.
d = 1 mm = 10−3 m.
The screen is placed at a distance D = 1 m away. Monochromatic light of wave length
λ = 500 nm = 5 × 10−7 m is used.
The distance between two successive maxima or two successive minima is
λDd=5×10−710−3=5×10−4m=0.5mm
Ten maxima are contained within a distance
10 × 0.5 mm = 5 mm
For a single slit pattern we have
sinθ=λa
The width of the central maxima is
2D sin θ=2Dλa=5mm∴a=2Dλ5×10−3=2×5×10−75×10−3=2×10−4m=0.2mm
