CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a double slit experiment, two incoherent sources are placed at the two slits. The intensity of sources at S1 is I0 and that at S2 is 3I0. Identity the correct statement.

A
Destructive interference will result at central position on screen.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
The resultant intensity at centre of screen will be 3I0.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The resultant intensity at any point on screen will be 4I0.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
The resultant intensity at any point on screen will be 2I0.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C The resultant intensity at any point on screen will be 4I0.
In case of incoherent sources, we will not get any interference pattern.

The intensity at all points on screen will be uniform.

IR=I1+I2

IR=I0+3I0=4I0

Hence, (C) is the correct answer.
Why this question?
Note: Two different sources of light are always incoherent despite being identical. It happens due to randomness of electrons in both objects. So, a single source need to be split by using lens or mirror to obtain coherent sources.

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hertz's Observations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon