In a F.C.C. lattice, atom X occupies the corner positions and atom Y occupies face centred positions. If all the atoms are missing from one of the face diagonal, the formula of the compound is

X_{2} B_{5}

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X_{3} Y_{10}

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X Y_{2}

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X_{2} Y_{3}

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Solution

The correct option is B $X_{3} Y_{10}$
If all the atoms are missing from one of the face diagonal, 2 atoms of X and 1 atom Y would be missing
$X_{\frac{6}{8}} Y_{\frac{5}{2}}; X_{0.75} Y_{2.5} X_{0.75 \times 4} Y_{2.5 \times 4}; X_{3} Y_{10}$

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In a F.C.C. lattice, atom X occupies the corner positions and atom Y occupies face centred positions. If all the atoms are missing from one of the face diagonal, the formula of the compound is

The correct option is B X3Y10If all the atoms are missing from one of the face diagonal, 2 atoms of X and 1 atom Y would be missing X68 Y52; X0.75 Y2.5X0.75×4 Y2.5×4; X3Y10

The correct option is B $X_{3} Y_{10}$
If all the atoms are missing from one of the face diagonal, 2 atoms of X and 1 atom Y would be missing
$X_{\frac{6}{8}} Y_{\frac{5}{2}}; X_{0.75} Y_{2.5} X_{0.75 \times 4} Y_{2.5 \times 4}; X_{3} Y_{10}$