In a face centered cubic lattice, atom A occupies the corner position and atom B occupies face centre position. If one atom of B is missing from one of the face centred points, the formula of compound is $A_{x} B_{5}$ . Find the value of x.___

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Solution

$A_{8 \times \frac{1}{8}} B_{5 \times \frac{1}{2}}$
$A_{1} B_{\frac{5}{2}}$
$A_{2} B_{5}$
$x = 2$

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In a face centered cubic lattice, atom A occupies the corner position and atom B occupies face centre position. If one atom of B is missing from one of the face centred points, the formula of compound is AxB5. Find the value of x.___

A8×18B5×12 A1B52 A2B5 x=2

In a face centered cubic lattice, atom A occupies the corner position and atom B occupies face centre position. If one atom of B is missing from one of the face centred points, the formula of compound is $A_{x} B_{5}$ . Find the value of x.___

$A_{8 \times \frac{1}{8}} B_{5 \times \frac{1}{2}}$
$A_{1} B_{\frac{5}{2}}$
$A_{2} B_{5}$
$x = 2$