In a factory all Supervisors are Engineers. One-third of all Engineers are Supervisors. Half of all Technicians are Engineers. Only one Technician is a Supervisor. Six Technicians are Engineers. If the number of Engineers is 60, how many Engineers are neither Supervisors nor Technicians?
This question can be repressented as a 3 set venn diagram as shown below
As all supervisors are engineers, we see that R = S = 0
One-third of all engineers are supervisors: y + z = (1/3)(x + y + z + p)
Half of all technicians are engineers: z + p = q. Only one technician is a supervisor: z = 1
Six technicians are engineers: p + z =6 → p = 5, q = 6 Number of engineers is 60: x + y + z + p = 60 → Number of supervisors = 1/3 * 60= 20
5 engineers are technicians but not supervisors
Engineers who are neither Supervisors nor Technicians.
Hence the 3 set venn diagram is: