Question

In a fair, there is a shop with gifts. You have to throw two dice at once (they are not identical). Before throwing, you have to predict the sum of the face values of the two dice. If you get the sum as predicted, you will get a free gift. Which number has the maximum chance of getting you the gift?

• A. 6
• B. 7
• C. 8
• D. 9

Answer 1

The correct option is B

7

Let us make a table to show all the possible outcomes.

$\begin{array}{ccccccc}& \text{1}& \text{2}& \text{3}& \text{4}& \text{5}& \text{6}\\ 1& 1,1& 1,2& 1,3& 1,4& 1,5& 1,6\\ 2& 2,1& 2,2& 2,3& 2,4& 2,5& 2,6\\ 3& 3,1& 3,2& 3,3& 3,4& 3,5& 3,6\\ 4& 4,1& 4,2& 4,3& 4,4& 4,5& 4,6\\ 5& 5,1& 5,2& 5,3& 5,4& 5,5& 5,6\\ 6& 6,1& 6,2& 6,3& 6,4& 6,5& 6,6\end{array}$

We can get the sum as 7 in maximum possible ways.

Probability of an event, P(E) = $\frac{numberoffavourableoutcomes}{totalnumberofoutcomes}$

P(getting the sum as 7) = $\frac{6}{36}$ = $\frac{1}{6}$

Similarly P(6) = P(8) = $\frac{5}{36}$ and P(9) = $\frac{4}{36}$ = $\frac{1}{9}$