In a falling head permeability test on a sample 12.2 cm high and 44.41 cm $^{2}$ in cross - sectional area, the water level in a standpipe of 6.25 mm internal diameter dropped from a height of 75 cm to 24.7 cm in 15 minutes. Find the coefficient of permeability

1.04 \times 10^{- 3} c m / s

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2.04 \times 10^{- 4} c m / s

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1.04 \times 10^{- 4} c m / s

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Solution

The correct option is C $1.04 \times 10^{- 4} c m / s$
$k = \frac{a L}{A t} l n [\frac{h_{1}}{h_{2}}]$

$= \frac{\frac{π}{4} (0.625)^{2} \times 12.2}{44.41 \times 15 \times 60} l n [\frac{75}{24.7}]$

$= 1.04 \times 10^{- 4} c m / s$

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In a falling head permeability test on a sample 12.2 cm high and 44.41 cm2 in cross - sectional area, the water level in a standpipe of 6.25 mm internal diameter dropped from a height of 75 cm to 24.7 cm in 15 minutes. Find the coefficient of permeability

The correct option is C 1.04×10−4cm/sk=aLAtln[h1h2] =π4(0.625)2×12.244.41×15×60ln[7524.7] =1.04×10−4cm/s

In a falling head permeability test on a sample 12.2 cm high and 44.41 cm $^{2}$ in cross - sectional area, the water level in a standpipe of 6.25 mm internal diameter dropped from a height of 75 cm to 24.7 cm in 15 minutes. Find the coefficient of permeability

The correct option is C $1.04 \times 10^{- 4} c m / s$
$k = \frac{a L}{A t} l n [\frac{h_{1}}{h_{2}}]$

$= \frac{\frac{π}{4} (0.625)^{2} \times 12.2}{44.41 \times 15 \times 60} l n [\frac{75}{24.7}]$

$= 1.04 \times 10^{- 4} c m / s$