In a family having 3 children, there may be no girl, one girl ,two girls, or three girls. So the probability of each is $\frac{1}{4}$ . Is this correct? justify your answer.

Open in App

Solution

No $,$ it is not correct $.$
Let boys be $B$ and girls be $G$
outcomes can be $B B B, G G G, B B G, B G B, G B B, G G B, G B G, B G G$
then Probability of $3$ girls $= 1 / 8$
Probability of $0$ girls $= 1 / 8$
Probability of $2$ girls $= 3 / 8$
Probability of $1$ girl $= 3 / 8$

Suggest Corrections

Similar questions

Q. Question 05.
In a family having three children, there may be no girl, one girl, two girls or three girls. So, the probability of each is

\frac{1}{4}

. Is this correcct ? Justify your answer.

Assume that each childborn is equally likely to be a boy or a girl .if a family has three children, then conditional probability that two children are girls given that family has at least one girl child is

Q. In a family with

4

children, the probability that there are at least two girls is

Q. Assume that each born child is equally likely to be a boy or a girl. If two families have two children each, then the conditional probability that all children are girls given that at least two are girls is :

Q. In a family there are 5 children two children are selected at random if they are found to be girls find the probability that the family has 3 girls and 2 boys.

Join BYJU'S Learning Program

In a family having 3 children, there may be no girl, one girl ,two girls, or three girls. So the probability of each is 14. Is this correct? justify your answer.

No, it is not correct.Let boys be B and girls be Goutcomes can be BBB,GGG,BBG,BGB,GBB,GGB,GBG,BGGthen Probability of 3 girls =1/8Probability of 0 girls =1/8Probability of 2 girls =3/8 Probability of 1 girl =3/8

In a family having 3 children, there may be no girl, one girl ,two girls, or three girls. So the probability of each is $\frac{1}{4}$ . Is this correct? justify your answer.

No $,$ it is not correct $.$
Let boys be $B$ and girls be $G$
outcomes can be $B B B, G G G, B B G, B G B, G B B, G G B, G B G, B G G$
then Probability of $3$ girls $= 1 / 8$
Probability of $0$ girls $= 1 / 8$
Probability of $2$ girls $= 3 / 8$
Probability of $1$ girl $= 3 / 8$