Question

In a family of 3 children, the probability of having at least one boy is

• A. $\frac{7}{8}$
• B. $\frac{1}{8}$
• C. $\frac{5}{8}$
• D. $\frac{3}{4}$

Answer 1

The correct option is A $\frac{7}{8}$

There are three children in the family:

The total number of outcomes = $2^3=8$

The number of favourable cases:

Atleast one of them is boy means all those cases in which we have either 1, 2, or 3 boys.

The eight combinations are BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

The probability of having atleast one boy in a family = $\frac{7}{8}$