In a family of 4 children The probability that there will be atleast one boy is
A
1316
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B
1516
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C
1416
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D
1216
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Solution
The correct option is C1516 The sample space will contain 24=16 outcomes. Now for atleast one boy, implies total outcomes - (all girls) =16−1 =15 Hence, the required probability is 1516.