Question

In a family of $4$ children The probability that there will be atleast one boy is

• A. $\frac{13}{16}$
• B. $\frac{15}{16}$
• C. $\frac{14}{16}$
• D. $\frac{12}{16}$

Answer 1

Answer: (B)

$\frac{15}{16}$

The sample space will contain $2^4=16$ outcomes.
Now for atleast one boy, implies
total outcomes - (all girls)
$=16-1$
$=15$
Hence, the required probability is $\frac{15}{16}$.