In a family, the father took one-fourth of the cake and he had three times more than the others had. The total number of family members is?

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Solution

The correct option is D $10$
Let cake weights $=$ x kg and no. of family members $=$ n
Father gets $= \frac{x}{4}$
Remaining $\frac{3 x}{4}$ distributed d equally among $(n - 1)$ member each gets $= \frac{3 x}{4 (n - 1)}$
$\frac{x}{4} = \frac{3 (3 x)}{4 (n - 1)}$
$n - 1 = 9$
$n = 10$ .

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In a family, the father took one-fourth of the cake and he had three times more than the others had. The total number of family members is?

The correct option is D 10Let cake weights = x kg and no. of family members=nFather gets=x4Remaining 3x4 distributed d equally among (n−1) member each gets =3x4(n−1)x4=3(3x)4(n−1)n−1=9n=10.

The correct option is D $10$
Let cake weights $=$ x kg and no. of family members $=$ n
Father gets $= \frac{x}{4}$
Remaining $\frac{3 x}{4}$ distributed d equally among $(n - 1)$ member each gets $= \frac{3 x}{4 (n - 1)}$
$\frac{x}{4} = \frac{3 (3 x)}{4 (n - 1)}$
$n - 1 = 9$
$n = 10$ .