In a figure, triangle ABC is right-angled at B. Given that AB = 9 cm, AC = 15 cm and D, E are the mid points of the sides AB and AC respectively, then calculate the length of BC

12 cm

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10 cm

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8 cm

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none of the above

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Solution

The correct option is A 12 cm
By Pythagoras theorem,
$∠ A B C$ is $90^{\circ}$
${A B}^{2} + {B C}^{2} = {A C}^{2}$
${B C}^{2} = {A C}^{2} - {A B}^{2}$
${B C}^{2} = 15^{2} - 9^{2} = 144$
$B C = \sqrt{144} = 12 c m$

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In a figure, triangle ABC is right-angled at B. Given that AB = 9 cm, AC = 15 cm and D, E are the mid points of the sides AB and AC respectively, then calculate the length of BC

The correct option is A 12 cmBy Pythagoras theorem, ∠ABC is 90∘ AB2+BC2=AC2BC2=AC2−AB2BC2=152−92=144BC=√144=12cm

The correct option is A 12 cm
By Pythagoras theorem,
$∠ A B C$ is $90^{\circ}$
${A B}^{2} + {B C}^{2} = {A C}^{2}$
${B C}^{2} = {A C}^{2} - {A B}^{2}$
${B C}^{2} = 15^{2} - 9^{2} = 144$
$B C = \sqrt{144} = 12 c m$