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Question

# In a first order reaction, if the time taken for completion of 50 percent of the reaction is t seconds, then the time required for completion of 99.9 percent of the reaction is

A
2 t
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B
10 t
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C
4 t
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D
3 t
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Solution

## The correct option is B 10 tWe know that for a first order reaction, the time taken for completion of 50 % is t=0.693k⇒k=0.693t When 99.9 % is completed, then 0.1 % or 11000 of the reactant will be left. The rate equation of first order reaction is kt′=2.303logA0At⇒0.693t×t′=2.303logaa/1000⇒0.693t×t′=2.303×3⇒t′=10 t

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