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Question

In a first order reaction, if the time taken for completion of 50 percent of the reaction is t seconds, then the time required for completion of 99.9 percent of the reaction is

A
2 t
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B
10 t
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C
4 t
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D
3 t
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Solution

The correct option is B 10 t
We know that for a first order reaction, the time taken for completion of 50 % is t=0.693kk=0.693t
When 99.9 % is completed, then 0.1 % or 11000 of the reactant will be left.
The rate equation of first order reaction is
kt=2.303logA0At0.693t×t=2.303logaa/10000.693t×t=2.303×3t=10 t

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