In a fission reaction
$_{92}^{236} U \to$ $^{117} X +$ $^{117} Y + n + n$
the average binding energy per nucleon of $X$ and $Y$ is $8.5 M e V$ whereas that of $^{236} U$ is $7.6 M e V$ .
The total energy liberated will be about :

200 keV

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2 MeV

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200 MeV

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2000 MeV

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Solution

The correct option is D $200 MeV$
Total energy liberated is,

$E = (234 \times 8.5 - 236 \times 7.6)$

$E = 195.4 M e V$

$E \approx 200 M e V$

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In a fission reaction23692U→ 117X+ 117Y+n+n the average binding energy per nucleon of X and Y is 8.5MeV whereas that of 236U is 7.6MeV . The total energy liberated will be about :

The correct option is D 200 MeVTotal energy liberated is, E=(234×8.5−236×7.6) E=195.4MeV E≈200MeV

In a fission reaction
$_{92}^{236} U \to$ $^{117} X +$ $^{117} Y + n + n$
the average binding energy per nucleon of $X$ and $Y$ is $8.5 M e V$ whereas that of $^{236} U$ is $7.6 M e V$ .
The total energy liberated will be about :

The correct option is D $200 MeV$
Total energy liberated is,

$E = (234 \times 8.5 - 236 \times 7.6)$

$E = 195.4 M e V$

$E \approx 200 M e V$