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Nuclear Fission

In a fission ...

Question

In a fission reaction $_{92} U^{236} \to X^{117} + Y^{117} + 2_{0} n^{1} + ε,$ The binding energy per nucleon of X and Y is 8.5 MeV where as of $_{92} U^{236}$ is 7.6 MeV. The total energy liberated will be about

200 KeV

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2 MeV

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200 MeV

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2000 MeV

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Solution

The correct option is C
200 MeV

Energy liberated $= 2 \times 117 \times 8.5 - 236 \times 7.6$

=200 MeV

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