wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a flexible balloon, 2 moles of SO2 having an initial volume of 1 kL at a temperature of 27oC is filled. (SO2 is a linear triatomic gas). The gas is first expanded to thrice its initial volume isobarically and then expanded adiabatically so as to attain its initial temperature. Assuming gas is ideal and R=253Jmol1K1 change in internal energy of the gas in the isobaric process is:


A
3.5×104J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1.2×106J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3×105J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5×103J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3.5×104J
In isobaric process the pressure remains constant.
Ideal gas equation: PV=nRT VT=nRP
V1T1=V2T2;
Given:
V1=1 kl=1000 cc
T1=27oC=(27+273)K=300K
1000300=3000T2
T2=9000K
For the triatomic gas SO2,γ=2+ff=2+77=97 since there are three translational, two rotational degrees of freedom making it a total of 7 degrees of freedom.
For the adiabatic process, Change in internal energy
dU=nCvΔT=nRγ1ΔT

=72nRΔT=72×2×R×(900300)

=72×2×253×(900300)=3.5×104

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Functions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon