In a fort 150 men had provisions for 45 days. After 10 days, 25 men left the fort. How long would the food last at the same rate?

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Solution

After 10 days:
For 150 men, provision will last (45 - 10) days = 35 days
$\Rightarrow$ For 1 man, the provisions will last
$= 150 \times 35$ days
And for (150 - 25) = 125 men, the provisions will last for
$= \frac{150 \times 35}{125} = 42 d a y s$

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In a fort 150 men had provisions for 45 days. After 10 days, 25 men left the fort. How long would the food last at the same rate?

After 10 days: For 150 men, provision will last (45 - 10) days = 35 days ⇒ For 1 man, the provisions will last =150×35 days And for (150 - 25) = 125 men, the provisions will last for =150×35125=42 days

After 10 days:
For 150 men, provision will last (45 - 10) days = 35 days
$\Rightarrow$ For 1 man, the provisions will last
$= 150 \times 35$ days
And for (150 - 25) = 125 men, the provisions will last for
$= \frac{150 \times 35}{125} = 42 d a y s$