In a fraction- the numerator is 2 less than the denominator- If 4 is added to the denominator- the fraction becomes 1-4 - Then find the product of the numerator and the denominator of the original fraction-

The correct option is B 8 Original fraction = x/x+2 x/x+6 = 1/4 x = 2 x × (x+2) = 8 ...

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In a fraction...

Question

In a fraction, the numerator is 2 less than the denominator. If 4 is added to the denominator, the fraction becomes $\frac{1}{4}$ . Then find the product of the numerator and the denominator of the original fraction?

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Solution

The correct option is B
8

Original fraction = $\frac{x}{x + 2}$

$\frac{x}{x + 6} = \frac{1}{4}$

$⟹ x = 2$

$⟹ x \times (x + 2) = 8$

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In a fraction, the numerator is 2 less than the denominator. If 4 is added to the denominator, the fraction becomes 14. Then find the product of the numerator and the denominator of the original fraction?

The correct option is B 8 Original fraction = xx+2 xx+6=14 ⟹x=2 ⟹x×(x+2)=8

In a fraction, the numerator is 2 less than the denominator. If 4 is added to the denominator, the fraction becomes $\frac{1}{4}$ . Then find the product of the numerator and the denominator of the original fraction?

The correct option is B
8

Original fraction = $\frac{x}{x + 2}$

$\frac{x}{x + 6} = \frac{1}{4}$

$⟹ x = 2$

$⟹ x \times (x + 2) = 8$