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Question

In a Fraunhoffer diffraction at single slit of width 'd' with incident light of wavelength 5500˚A, the first minimum is observed, at angle 30. The first secondary maximum is observed at an angle θ=

A
sin112
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B
sin114
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C
sin134
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D
sin132
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Solution

The correct option is B sin134
First minimum occurs at θ then sinθ=λa
sin30=λa
12=λa ........(1)
First secondary maxima occurs at θ then sinθ={n+(12)}(λa) where n=1
sinθ={1+(12)}(λa)
=(32)×(12)=(34)
θ=sin1(34)

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