In a frequency distribution, if the upper boundary of the class is 2 times the lower boundary of the class. What are the class mark and class length in terms of the lower limit?
A
Class marks is 2 times of lower boundary and class length is equal to lower boundary.
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B
Class marks is 1.5 times of lower boundary and class length is 2 times of lower boundary.
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C
Class marks is 1.5 times of lower boundary and class length is equal to lower boundary.
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D
Class marks is equal to lower boundary and class length is 1.5 times of lower boundary.
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Solution
The correct option is C Class marks is 1.5 times of lower boundary and class length is equal to lower boundary. Let, upper boundary = x lower boundary = y Given , x = 2y Class marks=upper boundary + lower boundary2
Class marks = x+y2
= 2y+y2 = 3y2 = 1.5y = 1.5 times of lower boundary
Class length = upper boundary - lower boundary = x - y = 2y - y = y = lower boundary