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Question

In a fuel cell, methanol is used as fuel and oxygen gas is used as an oxidizer.

The reaction is: CH3OH(l)+32O2(g)CO2(g)+2H2O(l)
At 298 K, standard Gibb's energies of formation for CH3OH(l), H2O(l) and CO2(g) are166.2,237.2 and 394.4 kJmo11 respectively.
If standard enthalpy of combustion of methanol is 726 kJmo11, efficiency of the fuel cell will be:

A
80%
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B
87%
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C
90%
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D
97%
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Solution

The correct option is D 97%
ΔG=ΔGprodΔGreact=2(237.2)394.4+166.2

=474.4394.4+166.2=702.6 kJ/mol
Efficiency =ΔGΔH×100

=702.6726×100

=96.7797%

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