Question

In a full wave rectifier, output is taken across a load resistor of $800\Omega$. If the resistance of diode in forward biased condition is $200\Omega$, the efficiency of rectification of ac power into dc power is

• A. $65\%$
• B. $40.6\%$
• C. $81.2\%$
• D. $80\%$

Answer 1

The correct option is A $65\%$

Here for full wave rectifier,

$R_L=800\Omega$

Forward bias resistance $=200\Omega$

Efficiency of full wave rectifier is,

$\eta =0.812\left[\frac{R_L}{R+R_L}\right]$

$\eta =0.812\left[\frac{800}{200+800}\right]=0.6496$

$\therefore \eta \approx 65\%$

Hence, $\left(A\right)$ is the correct answer.