Let us tn, tn+1 and tn+2 denote nth, (n + 1)th and (n + 2)th term of geometric progression respectively.
According to given condition,
tn = tn+1 + tn+2
i.e arn–1 = arn + arn+1
where, a denotes first term of g.p and r denote the common ratio.
Since r > 0 (given, g.p is positive series)
Therefore
Hence, the correct answer is option D.