In a G.P. the first, third and fifth terms may be considered as the first, fourth and sixteenth terms of an A.P. Then the fourth term of the A.P., knowing that its first term is 5 is
20
a=5,ar2=a+3d,ar4=a+15d
∴5r2=5+3d,5r4=5+15d
⇒r4=1+3d
⇒25r4=25+75d
⇒(5+3d)2=25+75d
⇒25+30d+9d2=25+75d
⇒9d2−45d=0
⇒d=50
⇒T4=a+3d=5+15=20