In a galvanic cell, 96500 C of + ve charge hours through an external circuit from electrode of higher potential. If the emf of the galvanic cell is 1.0V (i.e, 1.0 J/C), the electrical work done by the cell is
A
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B
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C
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D
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Solution
The correct option is B Electrical work = Potential difference × charge flown = 1V × 96500 C = 1.0J/C × 96500 C (∵ V = J/C) = 96,500 J