In a galvanic cell, the reactions taking place in the anodic half cell and the cathodic half cell will be:

reduction

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oxidation

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oxidation and reduction respectively

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reduction and oxidation respectively

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Solution

The correct option is C oxidation and reduction respectively
In a galvanic cell in anode half cell, oxidation of Zn takes place and in cathodic half cell
$C u^{2 t}$ gets reduced.
Hence, option C is correct.

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Similar questions

The following are some statements about galvanic cell.

1) The cell reaction will be obtained by summing up the reactions in the two half cells.

2) $E^{0}_{C e l l} = E^{0}_{C a t h o d e} - E_{A n o d e}^{0}$

3) $E {_{C e l l}}^{0} = E_{reduction electrode}^{0} - E_{oxidation electrode}^{0}$

4) $E^{0}_{C e l l} = E^{0}_{L . H . E} - E^{0}_{R . H . E}$

The correct combination is :

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

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