Question

In a galvanometer 5% of the total current in the circuit passes through it and remaining through shunt. If the
resistance of the galvanometer is G, the shunt resistance S connected to the galvanometer is

• A. $19G$
• B. $\frac{G}{19}$
• C. $20G$
• D. $\frac{G}{20}$

Answer 1

The correct option is B $\frac{G}{19}$

$(I-I_G)S=I_G{I}_{G}S=\frac{I_{G}G}{(I-I_G)}Here,IG=\frac{5}{100}I\therefore S=\frac{\frac{5}{100}IG}{I-\frac{5}{100}I}=\frac{G}{19}$