In a game, a man wins Rs. $5$ for getting a number greater than $4$ and loses Rs. $1$ otherwise, when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a number greater than $4$ . Find the expected value of the amount he wins/loses.

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Solution

number greater than 4 probability is $\frac{1}{3}$
number less than or equal to 4 is $\frac{2}{3}$
expected amount $3 (\frac{1}{3} * 5 + \frac{2}{3} * (- 1)) = 3$

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In a game, a man wins Rs. 5 for getting a number greater than 4 and loses Rs. 1 otherwise, when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a number greater than 4. Find the expected value of the amount he wins/loses.

number greater than 4 probability is 13number less than or equal to 4 is 23expected amount 3(13∗5+23∗(−1))=3

In a game, a man wins Rs. $5$ for getting a number greater than $4$ and loses Rs. $1$ otherwise, when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a number greater than $4$ . Find the expected value of the amount he wins/loses.

number greater than 4 probability is $\frac{1}{3}$
number less than or equal to 4 is $\frac{2}{3}$
expected amount $3 (\frac{1}{3} * 5 + \frac{2}{3} * (- 1)) = 3$