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Question

In a gaseous reaction A+2B2C+D, the initial concentration of B was 1.5 times that of A. At equilibrium, the concentrations of A and D were equal. The equilibrium constant Kc is:

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Solution

Assume initial conentration of B to be 3 and A to 2.

A+2B2C+D

Initial 2 3 - -
At eqm 21=1 32=1 2 1

So, Kc=2×2×11×1×1=4

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