Question

In a given circuit, if RMS voltage across resistance and capacitor are 25 V and 30 V, then peak voltage across inductor is given by $N\sqrt{2}\text{V}$ then value of $N$ is

Answer 1

$(\frac{50}{\sqrt{2}}{)}^2={25}^2+(V_L-30{)}^2$
$1250-625=(V_L-30{)}^2\Rightarrow 625=(V_L-30{)}^2$
$\pm 25=V_L-30\Rightarrow V_L=55or{V}_L=5$
$\therefore V_{L}peak=55\sqrt{2}or{V}_{L}peak=5\sqrt{2}\text{V}$