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Question


In a given circuit, switch S was closed for a long time and is opened in an instant. Charge on capacitor after time t=π1200sec after opening the switch is

A
1.73 mC
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B
14.1 mC
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C
10 mC
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D
5 mC
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Solution

The correct option is C 10 mC

Initial current through the inductor is VR=20050=4A.
After the switch is open, an LC circuit is formed with an angular frequency of w=1LC=200.
Threfore the equation from current is i=i0coswt=4cos200t.
Therfore the equation for charge is q=idt=4200sin200t
at t=π1200sec,q=4200sin(200×π1200)=10 mC

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