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Question

In a given fig. ACB=90o and CDAB then which one of the following is true?
718479_287c2f584859456c871c0ded64479bcf.PNG

A
BD2=AD×CD
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B
AD2=BD×CD
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C
CD2=BD×AD
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D
None of these
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Solution

The correct option is C CD2=BD×AD
Let ACD=θ
BCD=(90θ)
which DBC=θ {CDB=90}
Now, In CDB, In ACD
tanθ=CDBD tanθ=ADCD
equating both tanθ
CDBD=ADCD
CD2=BD×AD
Hence, the answer is CD2=BD×AD.


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