Question

In a given figure, BE is a median of $△ABD$. If the area of parallelogram ABCD is $24c{m}^2$. Then find the area of $△ABE$

Answer 1

In a parallelogram, triangle between the same parallels and on the same base have area which is equal to the half of that of parallelogram.

So, area of △ABD = $\frac{1}{2}\times 24$
$=12c{m}^2$ (1 marks)

Area of △ABE= $\frac{1}{2}\times areaof△ABD$ (Median divides the triangle into 2 equal areas)

Therefore,
Area of △ABE = $\frac{1}{2}\times 12$
$=6c{m}^2$(1 marks)