In a given figure in trapazium ABCD if AB || CD then value of x is

\frac{29}{8}

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\frac{8}{29}

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20

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\frac{1}{20}

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Solution

The correct option is D $20$
$\frac{O A}{O C} = \frac{O B}{O D} \Rightarrow \frac{2}{5} = \frac{x - 2}{2 x + 5}$
$\Rightarrow 4 x + 10 = 5 x - 10$
$\Rightarrow x = 20$

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Similar questions

A B ∥ C D

x

Find the area of a quadrilateral ABCD in which AB = 42cm, BC = 21cm, CD = 29 cm, DA = 34 cm and diagonal BD = 20 cm.

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