In a given figure in trapezium ABCD if AB || CD then value of x is -

\frac{29}{8}

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\frac{8}{29}

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20

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\frac{1}{20}

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Solution

The correct option is C $20$
Here, $\frac{O A}{O C} = \frac{O B}{O D} \Rightarrow \frac{2}{5} = \frac{x - 2}{2 x + 5}$

$\Rightarrow 4 x + 10 = 5 x - 10$

$\Rightarrow x = 20$

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In the given figure, ABCD is a trapezium in which
(i) AB || CD
(ii) $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2}$
(iii) AB = 5 cm

Find the value of CD .

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In a given figure in trapezium ABCD if AB || CD then value of x is -

The correct option is C 20Here, OAOC=OBOD⇒25=x−22x+5⇒4x+10=5x−10⇒x=20

The correct option is C $20$
Here, $\frac{O A}{O C} = \frac{O B}{O D} \Rightarrow \frac{2}{5} = \frac{x - 2}{2 x + 5}$

$\Rightarrow 4 x + 10 = 5 x - 10$

$\Rightarrow x = 20$