Question

In a given figure PQ||ST, $\angle$PQR $={110}^o$, $\angle$RST $={130}^o$ then value of $\angle$QRS is

• A. ${20}^o$
• B. ${50}^o$
• C. ${60}^o$
• D. ${70}^o$

Answer 1

Answer: (C)

${60}^o$

$\therefore (QRS={180}^o-({70}^o+{50}^o\left)\right)$
$={180}^o-{120}^o={60}^o$