Question

In a given process on an ideal gas $dW=0$ and $dQ<0,$ then the force of gas

• A. the temperature will decrease
• B. the volume will increase
• C. the pressure will remain constant
• D. the temperature will increase

Answer 1

The correct option is A the temperature will decrease

From first law of thermodynamics,
$dQ=dU+dW$
we have $dQ=dU(asdW=0)$
But $dQ<0$
$dU<0$
$n{C}_v\Delta T<0$
or $\Delta T<0$
Hence,the temperature will decrease