The correct option is D potential difference across AB can be greater than 20V at an instant.
XL=ωL=20Ω,
XC=1ωc=60Ω
z=√302+(60−20)2=50i=20sinωt50=25sinωt,irms=√25V1=irmsZ1=√25√302+602=6√10VV2=irmsZ1=√25×40=8√2V1 max=V1√2=6√10×√2=26.8
So V1 can take a value of 20 V.