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Question

In a given R - L circuit, I = 10 A and power loss in circuit is 1 kW, then

A
Inductance of the circuit is 310πH
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B
Resistance of the circuit is 103Ω
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C
Power factor is 0.5
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D
Voltage is 60o ahead of current
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Solution

The correct options are
A Inductance of the circuit is 310πH
C Power factor is 0.5
D Voltage is 60o ahead of current
P=i2R1000=102×RR=10Ω
V=IZ200=10R2+X2LXL=103
XL=ωLL=XL2π50=310π
ϕ=60o Power factor =cos ϕ=12

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