In a given square A B C D- if the area of triangle A B D is 36 cm 2- find i the area of triangle B C D- ii the area of the square A B C D-

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Standard IX

Mathematics

Line from Vertex Divides the Length of Opposite Side and Area

In a given sq...

Question

In a given square ABCD, if the area of triangle ABD is 36 cm², find (i) the area of triangle BCD; (ii) the area of the square ABCD.

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Solution

The diagonal of a square bisects it into two congruent triangles.

(i) Area of triangle BCD = Area of triangle ABD = 36 cm²

(ii) Area of square ABCD = 2 × Area of triangle ABD = 72 cm²

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In a given square ABCD, if the area of triangle ABD is 36 cm2, find (i) the area of triangle BCD; (ii) the area of the square ABCD.

The diagonal of a square bisects it into two congruent triangles. (i) Area of triangle BCD = Area of triangle ABD = 36 cm2 (ii) Area of square ABCD = 2 × Area of triangle ABD = 72 cm2

In a given square ABCD, if the area of triangle ABD is 36 cm², find (i) the area of triangle BCD; (ii) the area of the square ABCD.

The diagonal of a square bisects it into two congruent triangles.

(i) Area of triangle BCD = Area of triangle ABD = 36 cm²

(ii) Area of square ABCD = 2 × Area of triangle ABD = 72 cm²