Question

In a given U-tube (open at one-end) find out relation between p and $P_a$. Given $d_2=2\times 13.6gm/c{m}^3{d}_1=13.6gm/c{m}^3$

Answer 1

Pressure in a liquid at same level is same, i.e. at A - A -

$P_a+d_{2}Yg+X{d}_{1}g=P$
In C.G.S.
$P_a+13.6\times 2\times 25\times g+13.6\times 26\times g=P$
$P_a+13.6\times g$ [50 + 26] = P
$2P_a=P[P_a=13.6\times g\times 76]$