In a ||gm ABCD,if P and Q are midpoints if AB and CD respectively and ar(||gm ABCD)=16 cm2 then ar(||gm~APQD)=?
(a) 8 cm2
(b) 12 cm2
(c) 6 cm2
(d) 9 cm2
ANSWER:
(a) 8 cm2
Let the distance between AB and CD be h cm.
Then ar(||gm APQD ) = AP × h
= 1/2 × AB × h
(AP = 1/2AB )
= 1/2 × ar(||gm ABCD)
[ ar(|| gm ABCD) = AB × h )
∴ ar ( ||gm APQD ) = 1/2 × 16 = 8 cm2