In a golf torunament, if we designate the hole as the origin, and the putter (like a bat) is at -5.0 m at time 0 s, the average velocity of the ball when it reaches the hole is:

+ 5 m/s

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-1 m/s

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+1 m/s

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-5 m/s

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Solution

The correct option is C +1 m/s
Total displacement $s = 0 - (- 5) = 5 m$
Therefore, the average velocity $v = \frac{s}{t} = \frac{5 m}{5 s} = + 1 m / s$ .

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In a golf torunament, if we designate the hole as the origin, and the putter (like a bat) is at -5.0 m at time 0 s, the average velocity of the ball when it reaches the hole is:

The correct option is C +1 m/sTotal displacement s=0−(−5)=5 mTherefore, the average velocity v=st=5m5s=+1m/s.

The correct option is C +1 m/s
Total displacement $s = 0 - (- 5) = 5 m$
Therefore, the average velocity $v = \frac{s}{t} = \frac{5 m}{5 s} = + 1 m / s$ .