Question

In a $GP,T_5=3$. What is the product of the first nine terms?

Answer 1

Given,

$T_5=3$

$T_n=a{r}^{n-1}$

$3=a{r}^4$

Product of first nine terms,

$=a\times ar\times a{r}^2\times ........\times a{r}^8$

$=a^9{r}^{36}$

$=(a{r}^4{)}^9$

$=3^9$

$=19,683$