In a grid iron pendulum- there are 3 iron rods and 4 brass rods- Length of each brass rod is 50 cm- - of iron is 12 - 10-6 -C and - of Brass is 18 - 10-6- C- Length of each iron rod is

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Standard XII

Physics

Friction and Vertical Circular Motion Problems

In a grid iro...

Question

In a grid iron pendulum, there are 3 iron rods and 4 brass rods, Length of each brass rod is 50 cm. $α$ of iron is $12 \times 10^{- 6} /^{\circ} C$ and $α$ of Brass is $18 \times 10^{- 6} /^{\circ} C$ . Length of each iron rod is

50 cm

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100 cm

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120 cm

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60 cm

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Solution

The correct option is B 100 cm
Total change in lengths of the brass and iron rods must be same with equal change in temperature.
Hence $3 l_{i r o n} α_{i r o n} Δ θ = 4 l_{b r a s s} α_{b r a s s} Δ θ$
$⟹ l_{i r o n} = 2 l_{b r a s s} = 100 c m$

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Similar questions

Q. Assertion(A): In a grid pendulum, there are 3 iron rods and 4 brass rods. Length of each brass rod is

50 c m

α

of iron is

12 \times 10^{- 6} /^{o} C

and

α

of brass is

18 \times 10^{- 6} /^{o} C

. Length of each iron rod is

50 c m .

Reason(R): for grid iron pendulum

n_{1} l_{1} α_{1} + n_{2} l_{2} α_{2} = 1

Q. A Harrison's grid iron pendulum consists of

7

iron rods and

6

brass rod. If length of each brass rod is

20 c m

. What is the length of each iron rod

[\propto i r o n = 120 \times 10^{- 6} /^{\circ} C]

[\propto b r a s s = 20 \times 10^{- 6} /^{\circ} C]

Q. A brass rod at

30^{\circ} C

is observed to be 100 cm long when measured by a steel scale which is correct at

0^{\circ} C

α

for steel is

12 \times 10^{- 6} /^{\circ} C

and

α

for brass is

19 \times 10^{- 6} /^{\circ} C

. The correct length of brass rod at

0^{\circ} C

is :

An iron rod and another of brass, both at $27^{\circ} C$ differ in length by $10^{- 3} m$ . The coefficient of linear expansion for iron is $1.1 \times 10^{- 5}$ $/^{\circ} C$ and for brass is $1.9 \times 10 - 5$ $/^{\circ} C$ . The temperature at which both these rods will have the same length is

Q. The length of a brass rod at

0^{\circ} C

is 10m. Find its length at

100^{\circ} C

α

of brass is

18 \times 10^{- 6}^{\circ} C^{- 1}

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In a grid iron pendulum, there are 3 iron rods and 4 brass rods, Length of each brass rod is 50 cm.α of iron is 12×10−6/∘C and α of Brass is 18×10−6/∘C. Length of each iron rod is

The correct option is B 100 cmTotal change in lengths of the brass and iron rods must be same with equal change in temperature.Hence 3lironαironΔθ=4lbrassαbrassΔθ⟹liron=2lbrass=100cm

In a grid iron pendulum, there are 3 iron rods and 4 brass rods, Length of each brass rod is 50 cm. $α$ of iron is $12 \times 10^{- 6} /^{\circ} C$ and $α$ of Brass is $18 \times 10^{- 6} /^{\circ} C$ . Length of each iron rod is

The correct option is B 100 cm
Total change in lengths of the brass and iron rods must be same with equal change in temperature.
Hence $3 l_{i r o n} α_{i r o n} Δ θ = 4 l_{b r a s s} α_{b r a s s} Δ θ$
$⟹ l_{i r o n} = 2 l_{b r a s s} = 100 c m$