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Question

In a group of 10 children, there are 6 boys and 4 girls, 3 children are selected at random. Find the probability that the selected group have only one special girl.

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Solution

Total number of boys and girls=6+4=10
No. of ways of selecting 3 out of 10 boys and girls
=10C3=10.9×43.2.1=120
No. of ways of selecting 1 girl and 2 boys
=6C24C1=6×42×1×41=48
the required probability
=48120=615=25

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